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Find the Binding energy per neucleon for...

Find the Binding energy per neucleon for `""_(50)^(120)Sn`Mass of proton `m_(p)=1.00783U`, mass of neutron `m_(n)=1.00867U` and mass of tin nucleus `m_(Sn)=119.902199U`. (take 1 U = 931 MEV)

A

7.5 MeV

B

9.0 MeV

C

8.0 MeV

D

8.5 MeV

Text Solution

Verified by Experts

The correct Answer is:
D
B.E = `[Deltam] .c^(2)`
`M_("expected ") = ZM_(p) +(A-Z)M_(n)`
` = 50 [1.00783] +70 [1.00867]`
`M_("actual") = 119.902199`
B.E `= [ 50 [1.00783]+70 [1.00867] - 119.902199]xx31 `
` = 1020.56`
`("B.E")/("Nucleon") = (1020.56)/120 = 8.5` MeV .
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