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Two radioactive substances X and Y origi...

Two radioactive substances X and Y originally have `N_(1) and N_(2)` nuclei respectively. Half life of X is half of the half life of Y. After three half lives of Y, number of nuclei of both are equal. `(N_(1))/(N_(2))` The ratio N will be equal to :

A

`8/1`

B

`3/1`

C

`1/3`

D

`1/8`

Text Solution

Verified by Experts

The correct Answer is:
A
After n half life , no . Of nuclei undecayeed = `(N_(0))/(2^(n))`
Given `T_(1/2X)=(T_(1/2Y))/2`
So , 3 half life of Y = 6 half life of X
Given `N_(X) =N_(Y) (" after " 3T_(1/2Y))`
`(N_(1))/(N_(2)) =(2^(6))/(2^(3))=2^(3) =8/1 `.
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