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The half-life of ""^(198) Au is 3 days....

The half-life of `""^(198)` Au is 3 days. If atomic weight of `""^(198)` Au is 198 g/mol then the activity of 2 mg of `""^(198")` Au is [in disintegration/second] :

A

`6.06 xx 10^(8)`

B

`16.18 xx 10^(2)`

C

`2.67 xx 10^(12)`

D

`32.36 xx 10^(12)`

Text Solution

Verified by Experts

The correct Answer is:
B
`lambda = ("In2")/(t_(1/2)) = (In2)/(3xx24xx60xx60)`
`N = (2xx10^(-3))/(198) xx 6.022 xx 10^(23)`
Activity = `lambdaN `
`= (" In2")/(3xx24 xx 3600) xx (2xx10^(-3)xx6.022xx10^(23))/(198)`
` approx 16.18 xx 10^(12)` dps .
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