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From the given data, the amount of energ...

From the given data, the amount of energy required to break the nucleus of aluminium `""_(13)^(27)` Al is `"_______ "x xx 10^(-3)J.`
Mass of neutron = 1.00866 u
Mass of proton = 1.00726 u
Mass of Aluminium nucleus = 27.18846 u
(Assume 1 u corresponds to x J of energy)
(Round off to the nearest integer)

Text Solution

Verified by Experts

The correct Answer is:
27
Binding Energy = `DeltamC^(2)`
`Deltam = [13 xx 1.00726 +14 xx 1.00866-27.18846]`
`= 0.02716 = 27.16 xx10^(-3) u approx 27 u`
Binding Energy = `27 x xx 10^(-3) J ` .
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