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A silicon specimen is made into a P-type...

A silicon specimen is made into a `P`-type semiconductor by dopping, on an average, one helium atoms per `5xx10^(7)` silicon atoms. If the number density of atoms in the silicon specimen is `5xx10^(28) at om//m^(3)` then the number of acceptor atoms in silicon per cubic centimeter will be

A

`2.5xx10^(30)"atoms/cm"^(3)`

B

`1.0xx10^(13)"atoms/cm"^(3)`

C

`1.0xx10^(15)"atoms/cm"^(3)`

D

`2.5xx10^(36)"atoms/cm"^(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
`N_(A)=(5xx10^(28))/(5xx10^(7))=10^(21)//m^(3)`
Number of acceptor atoms -
`N_(A)=(10^(21))/((10^(2))^(3)cm^(3))=10^(15)//cm^(3)`
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