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A potential difference of 2V is applied ...

A potential difference of `2V` is applied between the opposite faces of a `Ge` crystal plate of area `1 cm^(2)` and thickness `0.5 mm`. If the concentration of electrons in `Ge` is `2xx10^(19)//m^(3)` and mobilities of electrons and holes are `0.36(m^(2))/(vol t-sec)` and `0.14 (m^(2))/(vol t-sec)` respectively, then the current flowing through the plate will be

A

`0.25` A

B

`0.45` A

C

`0.56` A

D

`0.64` A

Text Solution

Verified by Experts

The correct Answer is:
D
Conductivity `(sigma)="ne"(mu_(e)+mu_(h))`
= `2xx10^(19)xx1.6xx10^(-19)(0.36+0.14)=1.6(Omegam)^(-1)`
`R=rho(l)/(A)=(l)/(sigmaA)=(0.5xx10^(-3))/(1.6xx10^(-4))=(25)/(8)Omega`
`i=(V)/(R)=(2)/(25//8)=(16)/(25)=0.64` A .
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