In the case of constant alpha and beta o...

In the case of constant `alpha` and `beta` of a transistor

A

`alpha=beta`

B

`betalt1alphagt1`

C

`alphabeta=1`

D

`betagt1 alphalt1`

Verified by Experts

The correct Answer is:

D

`alpha=(I_(C))/(I_(E))"and"beta=(I_(C))/(I_(B))` , Hence `betagt1, alphalt1`

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