Home
Class 12
PHYSICS
For a common base configuration of PNP t...

For a common base configuration of `PNP` transistor `(l_(C))/(l_(E))=0.98`, then maximum current gain in common emitter configuration will be

A

12

B

24

C

6

D

5

Text Solution

Verified by Experts

The correct Answer is:
B
`alpha=0.96`
`beta=(alpha)/(1-alpha)=(0.96)/(1-0.96)=24`
Promotional Banner

Similar Questions

Explore conceptually related problems

For a transistor (I_(C))/(I_(E))=0.96 , then current gain for common emitter configuration

In a common-base configuration of a transistor (Delta i)/(Delta i_(e)) = 0.98 , then current gain in common emitter configuration of transistor will be

Current gain of common base configuration of a transistor is 0.9. It is used in common emitter configuration. Input and output resistances are 0.6k Omega , 50k Omega respectively. Find power gain.

In a common base configuration (transistor circuit) I_(E)=1mA, I_(C)=0.95mA . The value of base current is

In a transistor the current amplification alpha is '0.9', when connected in common base configuration. Now if the same transistor is connected in common emitter configurations and the change in ouput current is 4.5 mA, then the corresponding charnge in the input current is

The current gain of the amplifier in the common emitter configuration is 80. What is its current gain in common base configuration ?

For a transistor is common base configuration if beta is 100 , the value of current gain is is

For a transistor x=(1)/(alpha)&y=(1)/(beta) where alpha & beta are current gains in common base and common emitter configuration. Then