In an NPN transistor working as a common...

In an NPN transistor working as a common base amplifier, current gain is 0.96 and emitter current isb7.2mA .The base current is

A

`0.4` mA

B

`0.2` mA

C

`0.29` mA

D

`0.35` mA

Verified by Experts

The correct Answer is:

C

`alpha=(I_(C))/(I_(E))implies0.96=(I_(C))/(7.2mA)impliesI_(C)=6.912` mA
:. `I_(B)=I_(E)-I_(C)=0.288~~0.29 mA`

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