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A change of 0.04 V takes place between t...

A change of 0.04 V takes place between the base and the emitter when an input signal is connected to the CE transistor amplifier. As a result, `20 mu A` change takes place in the base current and a change of 2 mA takes place in the collector current. Find the input resistance and A.C. current gain

A

`2kOmega, 100`

B

`1kOmega, 100`

C

`2kOmega, 200`

D

`1kOmega, 200`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaV_(i)=0.04V`
`DeltaI_(B)=20mu A`
`DeltaI_(C)=2mA`
`r_(i)=(DeltaV_(i))/(DeltaI_(B))=(0.04)/(20xx10^(-6))=(4xx10^(4))/(20)=2kOmega`
`beta=(DeltaI_(C))/(DeltaI_(B))=(2xx10^(-3))/(20xx10^(-6))=100`
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