Home
Class 12
PHYSICS
The electrical conductivity of a semicon...

The electrical conductivity of a semiconductor increases when electromagnatic radiation of wavelength shorter than 2480 nm is incident on it. Find the band gap of the semiconductor. Given `h=6.63xx10^(-34)Js, and 1eV=1.6xx10^(-19)J`.

Text Solution

Verified by Experts

The correct Answer is:
`0.5`
Band gap, `E_g = hv = (hc)/lamda`
`=((6.63xx10^(-34))xx (3xx10^(8)))/(2480xx10^(-9))=8.02 xx10^(-20)J`
`=(8.02 xx10^(-20))/(1.6 xx10^(-19))~~0.5eV`
Promotional Banner

Similar Questions

Explore conceptually related problems

The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than 2480 nm is incident on it. The band gap in (eV) for the semiconductor is.

The electrical conductivity of semicondutor increases when electromagnetic radiation of wavelength shorter than 29800 Å is incident on it. The band gap for the semiconductor is

The electrical conductivity of semicondutor increases when electromagnetic radiation of wavelength shorter than 24800Å is incident on it. The band gap for the semiconductor is

The electricity conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than 2480nm is incident on it. The band gap (in eV) for the semiconductor is

The electrical conductivity of a semiconductor increases when electromagnatic radiation of wavelength shorter than 2480 nm is incident on it. The band gap (in eV) for the semiconductor is [hc=1242 eV nm]

The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than 1240 nm is incident on it. The forbidden band energy for the semi conductor is (in eV).

The electrical conductivity of a semiconductor increases wen electromagnetic radiations of wavelength shorter than 2480 nm is incident on it. The band gap (in eV) for the semiconductor is [ hc = 1242 e V n m ]

Conductivity of a semiconuctor increases when a radiation of wavelength is less than 2480 nm is incident on it. The forbidden gap is

A monochromatic source of light operating at 200W emits 4xx10^(-20) photons/sec. Find the wavelength of the light . (Given h = 6.63xx10^(-34) Js)