In the given circuit the current through Zener Diode is close to :

Options

A. 0.0mA
B. 6.7mA
C. 6.0mA
D. 4.0mA

Answer

A

Explanation

If we consider break down in Zener diode, then potential across `R_3` will be 10V and `R_1` will be 2V
So current in `R_3` will be `i_3 =10/1500 =2/300 A`
and current in `R_1` will be in = `i_1=2/500A`
`implies i_1lt i_3` which is not possible
`implies` Potential difference across Zener diode does not reach to break down voltage. So no current will flow through reverse biased Zener diode.