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In a common emitter amplifier circuit us...

In a common emitter amplifier circuit using an n-p-n transistor, the phase difference between the input and the output voltages will be:-

A

`180^@`

B

`45^@`

C

`90^@`

D

`135^@`

Text Solution

Verified by Experts

The correct Answer is:
A


`DeltaV_("CC") = DeltaV_(CE) + R_LDeltaI_C = 0`
or `DeltaV_(CE) =-R_LDeltaI_C`

The change in `V_(CE)` is the output voltage `v_0` From equation we get
`v_0=DeltaV_(CE) = -beta_(ac)R_LDeltaI_B`
The voltage gain of the amplifier is
`A_v=v_0/v_i=(DeltaV_(CE))/(rDeltaI_B)=-(beta_(ac)R_L)/r`
The negative sign represents that output voltage is opposite with phase with the input voltage.
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