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If an emitter current is changed by 4 mA...

If an emitter current is changed by 4 mA, the collector current changes by 3.5 mA. The value of `beta` will be :

A

0.5

B

7

C

3.5

D

`0.875 `

Text Solution

Verified by Experts

The correct Answer is:
C
Given : `DeltaI_E=4mA,DeltaI_C=3.5mA`
We know that, `alpha =(DeltaI_C)/(DeltaI_E)`
Also, `beta=alpha/(1-alpha)`,so
`beta=(7/8)/(1-7/8)=7/1`
`beta=7`
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