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If the maximum amplitude of an amoplitud...

If the maximum amplitude of an amoplitude modulated wave is 25 V and the minimum amplitude is 5V, the modulation index is

A

`1//5 `

B

`1//3`

C

`3//2`

D

`2//3`

Text Solution

Verified by Experts

The correct Answer is:
D
`A_(max) = A_c + A_m = 25 " "... (i)`
`A_("min") = A_c - A_m = 5 " "... (ii)`
Solving equation (i) and equations (ii), we get
`A_c = 15, A_m = 10 `
`mu = (A_m)/(A_C) =10/15=2/3`
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