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The maximum peak to peak voltage of an A...

The maximum peak to peak voltage of an AM wire is 24 mV and the minimum peak to peak voltage is 8 m V. The modulation factor is

A

`10% `

B

`20%`

C

`25% `

D

`50%`

Text Solution

Verified by Experts

The correct Answer is:
D
`V_("max")=A_C+A_m=24/2=12mV`
`V_("min")=A_c-A_m=8/2 =4mA`
`A_C=8mV`
`A_m =4mV`
modulation index
`mu = (A_m)/(A_C) =4/8 =1/2`
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