Home
Class 12
PHYSICS
An audio signal vm = 20 sin 2 pi (1500 t...

An audio signal `v_m = 20 sin 2 pi (1500 t)` amplitude modulates a carrier
` v_C = 80 sin 2pi (100,000t )`. The value of percent modulation is ___

Text Solution

Verified by Experts

The correct Answer is:
25
Given : `v_m = 20 sin [100 pi t +pi/4]`
`v_c = 80 [10^4 pi t +pi/6]`
We know that, modulation index `= A_m/A_c`
From given equations, `A_m = 20 and A_c= 80`
Percentage modulation index `= A_m/A_c xx100`
`implies 20/80 xx100 =25%`
The value of percentage modulation index is = 25.
Promotional Banner

Similar Questions

Explore conceptually related problems

An audio signal represented as 25 sin 2pi ( 2000 t) amplitude modulated by a carrier wave : 60 sin 2pi (100,000)t . The modulation index of the modulated signal is

An audio signal given by e_(s)=15 sin2pi(200t) modulates a carrier wave given by e_(s)=60 sin 2pi(100,000t) . If calculate ( a ) Percent modulation ( b ) Frequency spectrum of the modulated wave.

An audio signal given by e_1 = 12 sin 2pi (2000 t) amplitude modulates a sinusoidal carrier wave e^2 = 50 sin 2pi ( 100, I00t). What is the upper side band frequency?

A audio signal 20sin2pi(1500t) amplitude modulates 40sin2pi(10^(5))t . The depth of modulation is

A audio signal 15sin2pi(1500t) amplitude modulates 60sin2pi(10^(5))t . The depth of modulation is

The amplitude modulated current is given by i=70[1+0.06sin2900t]sin10^(6)t . The depth of modulation is

The amplitude modulated current is given by i=125[1+0.6sin2900t]sin10^(6)t . The depth of modulation is

An audio signal 25sin2pi(1400t) amplitude modulates 80sin2pi(10^(5)t) . The two side band frequencies are

An audio signal 5sin2pi(1600t) amplitude modulates 20sin2pi(10^(5)t) . The two side band frequencies are

In amplitude modulation carrier wave is C=4 sin 2000t and message wave M=2 sin 200t , Find out modulation index.