Integration part-1| My first vlog #shorts #youtubeshorts #shortsfeed #viralshorts #bfft

Integral part of (sqrt(2)+1)^(6) is

Integral of the form int[xf\'(x)+f(x)]dx can be evaluated by using integration by parts in first integral and leaving second integral as it is.Now answer the question: int(x+sinx)/(1+cosx)dx= (A) xtanx/2+c (B) x/2tanx/2+c (C) x/2tanx+c (D) none of these

Integral of the form int[xf\'(x)+f(x)]dx can be evaluated by using integration by parts in first integral and leaving second integral as it is.Now answer the question: int[1/(x^4+1)-(4x^4)/(x^4+1)^2]dx= (A) x^2/(x^4+1)+c (B) x^3/(x^4+1)+c (C) x/(x^4+1)+c (D) none of these

Integral of the form int[xf\'(x)+f(x)]dx can be evaluated by using integration by parts in first integral and leaving second integral as it is.Now answer the question: int[x^(x+1)(logx+1)+x^x]dx= (A) x^(x+2)+c (B) x^(x+1)+c (C) x^x+x+c (D) none of these

Integration By Parts|| Product Rule OF Integration||Measurement And Error|| Absolute Error|| Friction error|| Percentage Error|| Discussion-Sheet Section-1||Homework-4

Integration By Parts|| Product Rule OF Integration||Measurement And Error|| Absolute Error|| Friction error|| Percentage Error|| Discussion-Sheet Section-1||Homework-4

Divide 1224 into three parts such that first part be double that of second part and second part be 1/3 of the third part.

a) Derive and expression for the integrated rate equation for 1 first order reaction. b) Give an exmaple of pseudo first order reaction.

Divide ₹ 2340 into three partsnsuch that first part be double that of second part and second pary be (1)/(3) of the third part. Find the Third part amount ?