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A resistance of 40 Omega is connected t...

A resistance of `40 Omega` is connected to a source of alternating current rated 220 V, 50 Hz. Find the time taken by the current to change from its maximum value to the rms value :

A

2.5 ms

B

1.25 ms

C

2.5 s

D

0.25 s

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The correct Answer is:
To solve the problem of finding the time taken by the current to change from its maximum value to the RMS value in a circuit with a resistance of 40 ohms connected to an AC source of 220 V and 50 Hz, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the RMS Voltage and Frequency**: - The given voltage (V) is 220 V (RMS). - The frequency (f) is 50 Hz. 2. **Calculate the Maximum Voltage (V0)**: - The relationship between RMS voltage (V_RMS) and maximum voltage (V0) is given by: \[ V_0 = V_{RMS} \times \sqrt{2} \] - Substituting the given RMS voltage: \[ V_0 = 220 \times \sqrt{2} \approx 220 \times 1.414 \approx 311.8 \text{ V} \] 3. **Calculate the Maximum Current (I0)**: - Using Ohm's law, the maximum current (I0) can be calculated as: \[ I_0 = \frac{V_0}{R} \] - Where R is the resistance (40 ohms): \[ I_0 = \frac{311.8}{40} \approx 7.795 \text{ A} \] 4. **Determine the RMS Current (IRMS)**: - The RMS current (I_RMS) is given by: \[ I_{RMS} = \frac{I_0}{\sqrt{2}} \approx \frac{7.795}{\sqrt{2}} \approx \frac{7.795}{1.414} \approx 5.5 \text{ A} \] 5. **Relate Maximum Current to Time**: - The current in an AC circuit varies with time as: \[ I(t) = I_0 \sin(\omega t) \] - Where \(\omega = 2\pi f\) and \(f\) is the frequency (50 Hz): \[ \omega = 2\pi \times 50 \approx 314.16 \text{ rad/s} \] 6. **Set Up the Equation for RMS Current**: - We want to find the time \(t\) when the current is equal to the RMS current: \[ I_{RMS} = I_0 \sin(\omega t) \] - Substituting the values: \[ 5.5 = 7.795 \sin(314.16 t) \] 7. **Solve for sin(ωt)**: - Rearranging gives: \[ \sin(314.16 t) = \frac{5.5}{7.795} \approx 0.705 \] 8. **Find the Angle**: - Taking the inverse sine: \[ \omega t = \sin^{-1}(0.705) \approx 0.785 \text{ rad} \quad (\text{which is } \frac{\pi}{4}) \] 9. **Calculate Time t**: - Now, substituting back to find \(t\): \[ t = \frac{\omega t}{\omega} = \frac{\frac{\pi}{4}}{314.16} \approx \frac{0.785}{314.16} \approx 0.0025 \text{ s} \] - Converting to milliseconds: \[ t \approx 2.5 \text{ ms} \] ### Final Answer: The time taken by the current to change from its maximum value to the RMS value is approximately **2.5 milliseconds**. ---
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