In a vernier callipers, each cm on the main scale is divided into 20 equal parts. If tenth vernier scale division coincides with nineth main scale division . Then value of vernier contant will be _______`xx 10^(-2) `mm .

In a vernier callipers, 1 cm of the main scale is devided into 20 equal parts. 19 divisions of the main scale coincide with 20 divisions on the vernier scale . Find the least count of the instrument.

A vernier callipers has its main scale 10 cm equally divided into 250 parts its vernier scale is of 50 division and coincide with 15mm of the main scale the least count of the instrument is

10 vernier scale divisions VSD match with 9 main scale divisions MSD. Least count of the given vernier caliper is

Smallest division on the main scale of given Vernier calipers is 0.5 mm. Vernier scale has 25 divisions and these coincide with 24 main scale divisions. The least count of Vernier callipers is

In a vernier callipers, one main scale division is x cm and n divisions of the vernier scale coincide with (n-1) divisions of the main scale. The least count (in cm) of the callipers is :-

Consider a Vernier callipers in which each 1cm on the main scale is divided into 8 equal divisions and a screw gauge 5 divisions of the Vernier scale coincide with 4 divisions on the main scale and in the screw gauge, one complete rotation of the circular scale moves it by two divisions on the linder scale. Then:

A vernier calipers has 1mm marks on the main scale. It has 20 equal divisions on the Verier scale which match with 16 main scale divisions. For this Vernier calipers, the least count is