Home
Class 12
PHYSICS
A system of two blocks of masses m=2 kg ...

A system of two blocks of masses m=2 kg and M=8 kg is placed on a smooth table as shown in figure. The coefficient of static friction between two blocks is 0.5. The maximum horizontal force F that can be applied to the block of mass M so that the blocks move together will be :

A

`9.8N`

B

`39.2 N`

C

49 N

D

78.4 N

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • JEE MAINS 2022

    JEE MAINS PREVIOUS YEAR|Exercise Physics - Section B|40 Videos
  • JEE MAINS 2022

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS- SECTION A |19 Videos
  • JEE MAINS 2021

    JEE MAINS PREVIOUS YEAR|Exercise Physics (Section B )|10 Videos
  • JEE MAINS 2023 JAN ACTUAL PAPER

    JEE MAINS PREVIOUS YEAR|Exercise Question|360 Videos

Similar Questions

Explore conceptually related problems

The coefficient of static friction between two blocks is 0.5 and the table is smooth. The maximum horizontal force that can be applied to move the blocks together is N. (take g = 10 ms^(-2) )

The coefficient of static friction between the two blocks shown in figure is mu and the table is smooth. What maximum horizontal forced F can be applied to he block of mass M so that the block move together?

A block of mass m is placed on another block of mass M lying on a smooth horizontal surface as shown in the figure. The co-efficient of friction between the blocks is mu . Find the maximum horizontal force F (in Newton) that can be applied to the block M so that the blocks together with same acceleration? (M=3kg, m=2kg, mu=0.1, g=10m//s^(2))

Two blocks ( m = 0.5 kg and M = 4.5 kg) are arranged on a horizontal frictionless table as shown in figure. The coefficient of static friction between the two blocks is (3)/( 7) . Then the maximum horizontal force that can be applied on the larger block move together is "_____________" N. ( Round off to the Nearest Integer ) [Take as 9.8 ms^(-2) ]

A block of mass m=4kg is placed oner a rough inclined plane as shown in figure. The coefficient of friction between the block and the plane is mu=0.5 . A force F=10N is applied on the block at an angle of 30^(@) .

Coefficient of static friction between the two blocks in Fig. 7.124 is mu and the table is frictionless . Maximum horizontal force which can be applied on the lower such that the blocks move together , is :

Two blocks of masses m and 2m are placed on a smooth horizontal surface as shown in the figure. Find the acceleration of each block and normal reaction between two blocks if a horizontal force F_(0) is applied on (a) m and (b) 2m

Two block "A&B" of mass M_(A)=1kg&M_(B)=3kg are kept on a smooth table as shown in the figure.The coefficient of friction between "A&B" is "0.2" .The maximum force "F" that can be applied on "B" horizontally,so that the block "A" do not slide over the block "B" is Take g=10m/s^(2)andk=400N/m)

The two blocks, m= 10 kg and M = 50 kg are free to move as shown. The coefficient of static friction between the blocks is 0.5 and there is no friction between M and the ground. A minimum horizontal force F is applied to hold m against M that is equal to -