A cell, shunted by a `8Omega` resistance, is balanced across a potentiometer wire of length 3 m. The balancing length is 2 m when the cell is shunted by `4Omega` resistance. The value of internal resistance of the cell will be ______ `Omega`

In potentiometer experiment, a cell is balanced by length 120cm. When a cell is shunted by resistance of 5Omega , the balancing length is 80 cm. The internal resistance of cell is

In potentiometer experiment, a cell is balanced by length 120 cm. When a cell is shunted by resistance of 5Omega , the balancing length is 80 cm. The internal resistance of cell is

In an experiment to measure the internal resistance of a cell by potentiometer, it is found that the balance point is at a length of 2 m when the cell is shunted by a 4Omega resistance and at 3 m when cell is shunted by a 8Omega resistance. The internal resistance of cell is -

In an experiment to measure the internal resistance of a cell by a potentiometer, it is found that the balance point is at a length of 2 m when the cell is shunted by a 5 Omega resistance and is at a length of 3 m when the cell is shunted by a 10 Omega resistance, the internal resistance of the cell is then

In an experiment to measure the internal resistance of a cell by potentiometer, it is found that the balance point is at a length of 2 m when the cell is shuntedd by a 5 Omega resistance, and is at a length of 3 m when the cell is shunted by a 10 Omega resistance. The internal resistance of the cell is, then

When a Daniel cell is connected in the secondary circuit of a potentiometer, the balancing length is found to be 540 cm. If the balancing length becomes 500 cm. When the cell is short-circuited with 1Omega , the internal resistance of the cell is

A cell of e.m.f. 1.2 V is balanced by 150 cm of potentiometer wire. When the cell is shunted by a resistance of 4 Omega , the balancing length is reduced by 30 cm. What is the internal resistance of the cell ?