A pendulum of length 2 m consists of a wooden bob of mass 50 g. A bullet of mass 75 g is fired towards the stationary bob with a speed v. The bullet emerges out of the bob with a speed `v/3` and the bob just completes the vertical circle. The value of v is ______ `ms^(-1)` (if `g=10 m//s^2` ).

A pendulum consists of a wooden bob of mass m and length l . A bullet of mass m_(1) is fired towards the pendulum with a speed v_(1) . The bullet emerges out of the bob with a speed of (v_(1))//3 and the bob just completes motion along a vertical circle, then v_(1) is

A pendulum consists of a wooden bob of mass in and of length l . A bullet of mass m_(1) is fired towards the pendulum with a speed v_(1) . The bullet emerges out of the bob with a speed (v_(1))//3 and the bob just completes motion along a vertical circle. Then v_(1) is

A pendulum consists of a wooden bob of mass m and of length L . A bullet of mass m_(1) is fired towards the pendulum with a speed v_(1) . The bullet emerges out of the bob with a speed v_(1)//3 and the just completes motion along a vertical circle. Then v_(1) is:

A pendulum comsists of a wooden bob of mass m and length l . A bullet of mass m_1 is fired towards the pendulum with a speed v_1 and it emerges from the bob with speed v_1/3 . The bob just completes motion along a vertical circle. Then v_1 is

A pendulum consists of a wooden bob of mass M and length l . A bullet of mass m is fired towards the pendulum with a speed v . The bullet emerges immediately out of the bob from the other side with a speed of v//2 and the bob starts rising. Assume no loss of mass of bob takes place due to penetration. If the bob is just able to complete the circular motion, then tension at the lowest point just when the bob starts rising will be

A pendulum consists of a wooden bob of mass M and length l . A bullet of mass m is fired towards the pendulum with a speed v . The bullet emerges immediately out of the bob from the other side with a speed of v//2 and the bob starts rising. Assume no loss of mass of bob takes place due to penetration. What is the momentum transferred to the bob by the bullet?

A pendulum consists of a wooden bob of mass M and length l . A bullet of mass m is fired towards the pendulum with a speed v . The bullet emerges immediately out of the bob from the other side with a speed of v//2 and the bob starts rising. Assume no loss of mass of bob takes place due to penetration. If the bob stops where the string becomes horizontal then v is

A simple pendulum of length 1m has a wooden bob of mass 1kg . It is struck by a bullet of mass 10g moving with a speed of 200m//s . The bullet gets embedded into the bob. Obtain the height to which the bob rises before swinging back. Take g=10m//s^(2) .