Home
Class 12
PHYSICS
Two metallic plates form a parallel plat...

Two metallic plates form a parallel plate capacitor. The distance between the plates is `d` . A metal sheet of thickness `d/2` and of area equal to area of each plate is introduced between the plates. What will be the ratio of the new capacitance to the original capacitance of the capacitor?

A

`2:1`

B

`1:2`

C

`1:4`

D

`4:1`

Text Solution

AI Generated Solution

Promotional Banner

Topper's Solved these Questions

  • JEE MAINS 2022

    JEE MAINS PREVIOUS YEAR|Exercise Physics - Section B|40 Videos
  • JEE MAINS 2022

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS- SECTION A |19 Videos
  • JEE MAINS 2021

    JEE MAINS PREVIOUS YEAR|Exercise Physics (Section B )|10 Videos
  • JEE MAINS 2023 JAN ACTUAL PAPER

    JEE MAINS PREVIOUS YEAR|Exercise Question|360 Videos

Similar Questions

Explore conceptually related problems

Two metal plates form a parallel plate capacitor. The distance between the plates is d. A metal sheet of thickness d/2 and of the same area is indroduced between the plates. What is the ratio of the capacitances in the two cases?

Two metal plates form a parallel plate condenser. The distance between the plates in d. Now a metal plate of thickness d/2 and of same area is inserted completely between the plates, the capacitance

To reduce the capacitance of parallel plate capacitor, the space between the plate is

A metal foll of negative thickness is intorduced between two plates of a capacitor at the center. What will be the new capacitance of the capacitance ?

The capacitance of a parallel plate condenser with a separation of 4 mm between the plates is 7muF . If a mica sheet (K=6) of thickness 2 mm and of the same area is introduced betwenn the plates, its capacitance will be

The' distance between the plates of a parallel plate capacitor is d . A metal plate of thickness d//2 is placed between the plates. What will e its effect on the capacitance.

The distance between the plates fo a parallel plate capacitor is d. A metal plate of thickness d//2 is placed between the plates, what will be the new capacity ?

If a thin metal foil of same area is placed between the two plates of a parallel plate capacitor of capacitance C, then new capacitance will be

The separation between the plates of a parallel plate capacitor is d and the area of each plate is A. iff a dielectric slab of thickness x and dielectric constant K is introduced between the plates, then the capacitance will be