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Let AB and PQ be no vertical poles., 160...

Let AB and PQ be no vertical poles., 160 m apart from each other. Let C be the middle point of B and Q which are' feet of these two poles. Let `pi/8` and `theta` be the angles of elevation frnm C to P and A, .respectively. If the height of pole PQ is twice the height of pole AB then `tan^2theta` is equai to

A

`(3-2sqrt2)/2`

B

`(3+sqrt2)/2`

C

`(3-2sqrt2)/4`

D

`(3-sqrt2)/4`

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