The intensity of the light from a bulb incident on a surface is `0.22 W//m^2` . The amplitude of the magnetic field in this light-wave is ______ `xx 10^(-9)` T.
(Given : Permittivity of vacuum`in_0=8.85 xx 10^(-12) C^2 N^(-1) m^(-2)`, speed of light in vacuum `c=3 xx 10^8ms^(-1)` )

A point source surrounded by vacuum emits an electromagnetic wave of frequency of 900 kHz. If the power emitted by the source is 15 W, the amplitude of the electric field of the wave (in x10^(-3) V/m) at a distance 15 km from the source is: find the value x?? "("(1)/(4pi in_(0))=9xx10^(9)(Nm^(2))/(C^(2)) and speed of light in vacuum =3xx10^(8)ms^(-1) )

A 27 mW laser beam has a cross-sectional maximum electric field in this electromagnetic wave is given by : [Given permittivity of space in_(0) = 9 xx 10^(12) SI units, Speed of light c= 3 xx 10^(8) m//s ]

A plane electromagnetic wave , has frequency of 2.0 xx 10^(10) Hz and its energy density is 1.02 xx 10^(-8)J//m^(3) in vacuum. The amplitude of the magnetic field of the wave is close to ((1)/( 4 pi epsi_0)=9xx 10^(9) (Nm^(2))/(C^(2)) and " speed of light "= 3 xx 10^(8) ms^(-1)) :

A beam of light has intensity 2. 8xx 10^(14) W m^(-2) .Calculate the value of amplitude of electric field magnetic field of the beam .

A radiation is emitted by 1000 W bulb and it generates an electric field and magnetic field at P, placed at a distance of 2 m. The efficiency of the bulb is 1.25%. The value of peak electric field at Pis "x"xx10^(-1)V//m . Value of x is_ (Rounded-off to the nearest integer) [Take epsi_0=8.85xx10^(-12)C^2N^(-1)m^(-2),c=3xx10^8ms^(-1)

The magnetic field of a plane electromagnetic wave is vecB = 3 xx 10^(-8) sin[200 pi (y + ct)] hati T Where c = 3 xx 10^(8) ms^(-1) is the speed of light. The corresponding electric field is:

Calculate the energy in MeV equivalent to the rest mass of an electron . Given that the rest mass of an electron , m=9.1 xx 10^(-31) kg , 1MeV = 1.6 xx 10^(-13) J and speed of light , c= 3 xx 10 ^(8) ms ^(-1) .

Light enters from air to diamond with refractive index 2.42 What is the speed of light in diamond ? Given, speed light in air is 3xx10^8ms^(-1) .

Suppose that intensity of a laser is ((315)/(pi)) W//m^2 . The rms electric field, in units of V/m associated with this source is close to the nearest with this source is close to the nearest integer is _______ . (in_0 = 8.86 xx 10^(-12) C^2 Nm^(-2) , c= 3 xx 10^8 ms^(-1))