As per the given figure, two plates A and B of thermal conductivity K and 2 K are joined together to form a compound plate. The thickness of plates are 4.0 cm and 2.5 cm respectively and the area of cross-section is 120 cm2 for each plate. The equivalent thermal conductivity of the compound plate is `(1 +5/alpha)` K, then the value of `alpha` will be _______

Two parallel plates A and B are joined together to form a compound plate . The thicknesses of the plate are 4.0cm and 2.5cm respectively and the area of cross section is 100cm^(2) for each plate. The thermal conductivities are K_(A)=200Wm^(-1) ^(@)C^(-1) for the palte B. The outer surface of the plate A is maintainned at 100^(@)C and the outer surface of the plate A is maintained at 100^(@)C . and the outer surface of the plate B is maintained at 0^(@)C. Find (a) the rate of heat flow through any cross section, (b) the temperature at the interface and (c) the equivalent thermal conductivity of the compound plate.

Consider a compound slab consisting of two different material having equal thickness and thermal conductivities K and 2K respectively. The equivalent thermal conductivity of the slab is

Two rods of the same length and diameter, having thermal conductivities K_(1) and K_(2) , are joined in parallel. The equivalent thermal conductivity to the combinationk is

Two rods of length l and 2l thermal conductivities 2K and K are connected end to end. If cross sectional areas of two rods are eual, then equivalent thermal conductivity of the system is .

Two identical plates with thermal conductivities K and 3K are joined together to form a single plate of double thickness. The equivalent thermal conductivity of one composite plate so formed for the flow of heat through its thickness is.

Two identical plates of different metals are joined to form a single plate whose thickness is double the thickness of each plate. If the coefficients of conductivity of each plate are 2 and 3 respectively, Then the conductivity of composite plate will be

A slab consists of two layers of different materials of the same thickness and having thermal conductivities K_(1) and K_(2) . The equivalent thermal conductivity of the slab is

If two metallic plates of equal thickness and thermal conductivities K_(1) and K_(2) are put together face to face and a common plate is constructed, then the equivalent thermal conductivity of this plate will be