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Resistance of the wires is measured as 2...

Resistance of the wires is measured as `2Omega and 3Omega` at `10^(@)C` and `30^(@)C` respectively. Temperature co-efficient of resistance of the material of the wire is :

A

`0.033"^(@)C^(-1)`

B

`-0.033"^(@)C^(-1)`

C

`0.011"^(@)C^(-1)`

D

`0.055"^(@)C^(-1)`

Text Solution

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The correct Answer is:
To find the temperature coefficient of resistance (α) of the material of the wire, we can use the formula for resistance change with temperature: \[ R = R_0 (1 + \alpha \Delta T) \] Where: - \( R \) is the resistance at temperature \( T \), - \( R_0 \) is the resistance at the reference temperature (usually taken as 0°C), - \( \alpha \) is the temperature coefficient of resistance, - \( \Delta T \) is the change in temperature. ### Step-by-step Solution: 1. **Identify Given Values:** - Resistance at \( 10°C \) (let's call it \( R_1 \)): \( 2 \, \Omega \) - Resistance at \( 30°C \) (let's call it \( R_2 \)): \( 3 \, \Omega \) - Initial temperature for \( R_1 \): \( T_1 = 10°C \) - Initial temperature for \( R_2 \): \( T_2 = 30°C \) 2. **Calculate Change in Temperature:** - For \( R_1 \): \( \Delta T_1 = T_1 - 0 = 10°C \) - For \( R_2 \): \( \Delta T_2 = T_2 - 0 = 30°C \) 3. **Set Up Equations Using the Resistance Formula:** - For \( R_1 \): \[ R_1 = R_0 (1 + \alpha \Delta T_1) \implies 2 = R_0 (1 + 10\alpha) \quad \text{(Equation 1)} \] - For \( R_2 \): \[ R_2 = R_0 (1 + \alpha \Delta T_2) \implies 3 = R_0 (1 + 30\alpha) \quad \text{(Equation 2)} \] 4. **Divide Equation 2 by Equation 1:** \[ \frac{3}{2} = \frac{R_0 (1 + 30\alpha)}{R_0 (1 + 10\alpha)} \] Simplifying gives: \[ \frac{3}{2} = \frac{1 + 30\alpha}{1 + 10\alpha} \] 5. **Cross Multiply to Eliminate the Fraction:** \[ 3(1 + 10\alpha) = 2(1 + 30\alpha) \] Expanding both sides: \[ 3 + 30\alpha = 2 + 60\alpha \] 6. **Rearranging the Equation:** \[ 3 - 2 = 60\alpha - 30\alpha \] \[ 1 = 30\alpha \] 7. **Solve for α:** \[ \alpha = \frac{1}{30} \] 8. **Convert to Decimal:** \[ \alpha \approx 0.0333 \, \text{°C}^{-1} \] ### Final Answer: The temperature coefficient of resistance \( \alpha \) is approximately \( 0.0333 \, \text{°C}^{-1} \).

To find the temperature coefficient of resistance (α) of the material of the wire, we can use the formula for resistance change with temperature: \[ R = R_0 (1 + \alpha \Delta T) \] Where: - \( R \) is the resistance at temperature \( T \), - \( R_0 \) is the resistance at the reference temperature (usually taken as 0°C), - \( \alpha \) is the temperature coefficient of resistance, ...
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