In the given circuit, the magnitude of `V_(L) and V_(C)` are twice that of `V_(R)`. Given that f = 50 Hz, the inductance of the coil is `(1)/(Kpi)mH`. The value of K is ________

Answer

JEE main answer is zero and Reso answer is `(1)/(100)`

Explanation

`v=sqrt(v_(2)^(2)+(v_(L)-v_(C))^(2))`
`v_(L)=v_(C)=v_(R)`
`v_(S)=v_(R)=220V`
`l_(rms)=(220)/(5)=44A`
`X_(L)=(440)/(44)=10Omega`
`L=(10)/(100pi)=(1)/(10_(pi))Hz`
`(1)/(Kpi)xx10^(3)=(1)/(10pi)`
`K=(1)/(100)`