A capacitor `C_(1)` of capacitance `5muF` is charged to a potential of 30 V using a battery. The battery is then removed and the charged capacitor is connected to an uncharged capacitor `C_(2)` of capacitance `10muF` as shown in figure. When the switch is closed charge flows between the capacitors. At equilibrium the charge on the capacitor `C_(2)` is _________ `muC`

Answer

100

Explanation

`V=(C_(1)V_(1)+C_(2)V_(2))/(C_(1)+C_(2))`
`=(5xx30+0)/(5+10)=10`
`Q_(2)=C_(2)V=10xx10=100muC`