Home
Class 12
PHYSICS
A point object O is kept at a distance O...


A point object `O` is kept at a distance `OP=u` The radius of curvature of the spherical surface APB is `CP=R` The refractive index of the media are `n_1` and `n_2` which are as shown in the diagram . Then,
(A) if `n_1gtn_2`, image is virtual for all values of u
(B) if `n_2=2n_1` image is virtual when `Rgtu`
(C) The image is real for all values of `u`, `n_1` and `n_2` here, the correct statements is/are

A

Only (2)

B

Both (1) and (2)

C

Only (1)

D

(1), (2) and (3)

Text Solution

Verified by Experts

The correct Answer is:
B
`(n_(2))/(v) - (n_(1))/(u) = (n_(2) - n_(2))/(R )`
(1) and (2) statement are correct.
Promotional Banner

Similar Questions

Explore conceptually related problems

Real image and Virtual image

A small point object is placed at O at a distance of 0.60 metre in air from a convex spherical surface of refractive index 1.5 .If the radius of the curvature is 25cm then what is the position of the image on the principal axis.

A point object is placed at the centre of a glass sphere of radius 6cm and refractive index 1.5. The distance of virtual image from the surface is

A real object is kept in air and refraction occurs at the convex boundry of a spherical glass surface. For the image to be real, the real object distance (n_(g)=3//2)

For the spherical interface shown in the figure, the two different media with refractive indices n_1 = 1.4 and n_2 =1.25 are present as shown. The image will be formed at

A point object is placed at the center of a glass sphere of radius 6cm and refractive index 1.5. The distance of virtual image from the surface is

A small point objects is placed in air at a distance of 60 cm from a convex spherical refractive surface of mu = 1.5 . If radius of curvature of spherical surface is 25 m , calculate the position of the image and the power of the refracting surface.