Home
Class 12
PHYSICS
The ratio of angle of minimum deviation ...

The ratio of angle of minimum deviation of a prism in air and when dipped in water will be `(mu_(g)=3//2 and mu_(w)=4//3)`

A

`1//8`

B

`1//2`

C

`3//4`

D

`1//4`

Text Solution

Verified by Experts

The correct Answer is:
D
`delta_(m) = A(n_(21) - 1)`
`rArr (delta_(m))/(delta_(a)) = (n_(gw) - 1)/( n_(ga - 1) = ((9)/(8) - 1)/((3)/(2) - 1) = (1)/(4) `.
Promotional Banner

Similar Questions

Explore conceptually related problems

The ratio of angle of minimum deviation of a prism in air and when dipped in water will be (._(a)mu_(g)=3//2 and ._(a)mu_(w)=4//3)

The ratio of the angle of minimum deviation of a prism in air and when dipped in water will be (""_(a)mu_(g) = (2)/(3) and ""_(w)mu_(g) = (9)/(8)) and

The deviation produced by a thin glass prism placed in air, when immersed in water is [Given ""_(a)mu_(g) = 3//2 and ""_(a)mu_(w) = 4//3 ]

Focal length of a convex lense in air is 10cm . Find its focal length in water. Given that mu_g=3//2 and mu_w=4//3 .

What is the apparent position of an object below a rectangular block of glass 6 cm thick, if a layer of water 4 cm thicke ia on the top of the glass ? Given ^(a)mu_(g) = 3//2 and ^(a)mu_(w) = 4//3 .

Show that the angle of deviation produced by a thin prism is reduced to one fourth (w.r.t. air) when it is immersed in water. Given .^a mu_g = 3//2 and .^a mu_g = 4//3 .

The angle of minimum deviation for a glass prism with mu=sqrt3 equals the refracting angle of the prism. What is the angle of the prism?

The angle of minimum deviation for a glass prism with mu=sqrt3 equals the refracting angle of the prism. What is the angle of the prism?

Critical angle of glass is theta_(1) and that of water is theta_(2) . The critical angle for water and glass surface would be (mu_(g)=3//2, mu_(w)=4//3)