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For a prism of refractive index 1.732, t...

For a prism of refractive index `1.732`, the angle of minimum deviation is equal to the angle of the prism. The angle of the prism is

A

`80^(@)`

B

`70^(@)`

C

`60^(@)`

D

`50^(@)`

Text Solution

Verified by Experts

The correct Answer is:
C
`n = (sin ((A + delta_(m))/(2)))/(sin A//2) = (2 sin A// 2 cos A//2)/(sin A//2) [ "as " delta_(m)= A]`
`rArr " " n= 2 cos A//2 `
`rArr (sqrt(3))/(2) = cos A//2 rArr A//2 = 30^(@) rArr A = 60^(@)` .
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