When the object is self-luminous, the re...

When the object is self-luminous, the resolving power of a microscope is given by the expression

A

`(2mu sin theta )/(1.22 lambda)`

B

`(mu sin theta )/(lambda)`

C

`(2mu cos theta )/(1.22 lambda )`

D

`(2 mu )/( lambda )`

Verified by Experts

The correct Answer is:

A

`d_(min) = (1.22 lambda )/(2 mu sin theta)`
and resolving power = `(2 mu sin theta)/(1.22 lambda)`.

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