What should be the width of each slit to obtain `10` maxima of the double slit interference pattern within the central maximum of single slit diffraction pattern ? (NCERT Solved example)

Answer

`0.2`

Explanation

If a is which of single slit , then for central maximum of single slit diffraction pattrn
Total angular width,
`2 theta = (2 lambda)/(a)` . . . (i)
For 10 maxima of double slit interference pattem , total angular width
`2 theta = 10 (lambda)/( d) ` . . . (ii)
From (i) and (ii) , `(2 lambda)/( a) = (10 lambda)/(d)`
`a = (d)/( 5) = (1)/(5) = 0.2 ` m m