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A spherical surface of radius of curvatu...

A spherical surface of radius of curvature R separates air (refractive index 1.0) from glass (refractive index 1.5). The centre of curvature is in the glass. A point object P placed in air is found to have a real image Q in the glass. The line PQ cuts the surface at a point O, and `PO=OQ`. The distance `PO`

A

5 R

B

3 R

C

2 R

D

1.5 R

Text Solution

Verified by Experts

The correct Answer is:
A
For spherical surface
`(n_(2))/(v) - (n_(1))/( u) = (n_(2) - n_(1))/( R)`
`rArr (1.5)/(+OQ) - (1)/((-OP)) = (1.5 -1)/( R)`
`rArr OP = 5R ` [ `:. OQ = OP` ]
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