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The value of numerical aperture of the o...

The value of numerical aperture of the objective lens of a microscope is `1.25`.If light of wavelength `5000A^(@)` is used then minimum separation between two points,to be seen as distinct is ?

A

` 0.12 mu m`

B

` 0.48 mu m`

C

`0.38 mu m`

D

`0.24 mu m`

Text Solution

Verified by Experts

The correct Answer is:
D
`d_("min") = (1.22 lambda)/( 21 mu sin theta )`
` mu sin theta ` = numerical aperture = 1.25
`d_("min") = (1 . 22 xx 5 xx 10 ^(-7))/( 2 xx 1.25) = 0.24 mu m `
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