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In Young's double slit experiment, dista...

In Young's double slit experiment, distance between two sources is 0.1mm. The distance of screen from the sources is 20cm. Wavelength of light used is `5460 Å`. Then, angular position of first dark fringe is approximately

A

`0.08^(@)`

B

`0.16^(@)`

C

`0.20^(@)`

D

`0.313^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D
Angular position of `1^(st)` dark fringe
`theta= (lambda)/(d)= (5460 xx 10^(-10))/(0.1 xx 10^(-3))xx (180)/(pi)= 0.313^(@)`
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