Home
Class 12
PHYSICS
In the Young's double-slit experiment,th...

In the Young's double-slit experiment,the intensity of light at a point on the screen where the path difference is `lambda` is `K` (`lambda` being the wave length of light used).The intensity at a point where the path difference is `lambda/4`, will be

A

`K//2`

B

Zero

C

K

D

`k//4`

Text Solution

Verified by Experts

The correct Answer is:
A
Phase difference `(Deltaphi)= (2jpi)/(lambda) xx "Path difference"`
and Intensity (I)= `4I_(0)cos^(2)(phi)/(2)`
When path difference `(Deltax)= lambda`
`Deltaphi= (2pi)/(lambda) xx lambda= 2pi`
`I_("max")= 4I_(0)= K implies 2I_(0)= (K)/(2)`
When path difference `(Deltax)= (lambda)/(4)`
`Deltaphi= (2pi)/(lambda) xx (lambda)/(4) = (pi)/(2)`
`I= 4I_(0) cos^(2)(pi)/(4)= 2I_(0) :. I= (K)/(2)`
Promotional Banner

Similar Questions

Explore conceptually related problems

In a Young's double slit experiment , the intensity of light at a point on the screen where the path difference is lambda is k units. Find the intensity at a point where the path difference is (a) (lambda)/(4) (b) (lambda)/(3) and (c) (lambda)/(2)

In Young's double slit experiment the intensity of light at a point on the screen where the path difference lambda is K. The intensity of light at a point where the path difference is (lambda)/(6) [ lambda is the wavelength of light used] is

In Young's double-slit experimetn, the intensity of light at a point on the screen, where the path difference is lambda ,is I . The intensity of light at a point where the path difference becomes lambda // 3 is

In a Young's double slit experiment, the intensity of light at a point on the screen where the path difference is lambda is K units. Find the intensities at a point, where path diff. is (i) lambda//4 (ii) lambda//2 .

In a Young's double slit experiment, using mono-chromatic light of wavelength lambda , the intensity of light at a point on the screen where the path defference is lambda is k units. Find the intensity at a point where the path difference is lambda//3 .

In Young's double slit experiment, the intensity of light at a point on the screen where the path difference is lambda=l . The intensity of light at a point where the path difference becomes lambda//3 is

In Young's double slit experiment, the intensity of light at a point on the screen where path difference is lambda is I. If intensity at another point is I/4, then possible path differences at this point are

In a Young's double slit experiment the intensity at a point where tha path difference is (lamda)/(6) ( lamda being the wavelength of light used) is I. If I_0 denotes the maximum intensity, (I)/(I_0) is equal to