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A single slit of width 0.20 mm is illumi...

A single slit of width `0.20 mm` is illuminated with light of wavelength `500 nm`. The observing screen is placed `80 cm` from the slit. The width of the central bright fringe will be

A

1 mm

B

2mm

C

4 mm

D

5 mm

Text Solution

Verified by Experts

The correct Answer is:
C
Width of central bright fringe = `(2lambdaD)/(d)= ( 2xx 500 xx 10^(-9) xx 80 xx 10^(-2))/(0.2 xx 10^(-3))= 4 xx 10^(-3) m= 4mm`
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