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Light of wavelength lambda=5000Å falls n...

Light of wavelength `lambda=5000Å` falls normally on a narrow slit. A screen is placed at a distance of `1m` from the slit and perpendicular to the direction of light. The first minima of the diffraction pattern is situated at `5mm` from the centre of central maximum. The width of the slit is

A

0.1 mm

B

1.0 mm

C

0.5 mm

D

0.2 mm

Text Solution

Verified by Experts

The correct Answer is:
A
Position of nth minima
`x_(n)= (nlambdaD)/(a)`
`implies 5 xx 10^(-3) = (1 xx 5000 xx 10^(-10) xx 1)/(a)`
`implies a= 10^(-4)m= 0.1 mm`
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