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A single slit Fraunhofer diffraction pat...

A single slit Fraunhofer diffraction pattern is formed with white light. For what wavelength of light the third secondary maximum in the diffraction pattern coincides with the secondary maximum in the pattern for red light of wavelength 6500 Å ?

A

4400 Å

B

4100 Å

C

4642.8 Å

D

9100 Å

Text Solution

Verified by Experts

The correct Answer is:
C
For maxima `x_(n)=((2n+1)lambdaD)/(2a)`
`implies ((2 xx 3+ 1)lambda_(1)D)/(2a)= ((2 xx 2+ 1) xx 6500 xx 10^(-10)D)/(2a)`
`lambda_(1)= (5)/(7) xx 6500 Å= 4642.8 Å`
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