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A single slit of width a is illuminated ...

A single slit of width a is illuminated by violet light of wavelength `400nm` and the width of the diffraction pattern is measured as y. When half of the slit width is covered and illuminated by yellow light of wavelength `600nm`, the width of the diffraction pattern is

A

The pattern vanishes and the width is zero

B

`y//3`

C

3y

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
Width of central maxima = `y= (2lambdaD)/(d)`
`implies (y.)/(y)= (lambda.)/(d.) xx (d)/(lambda)= (600)/(d//2) xx (d)/(400)implies y.= 3y`
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