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Angular width of central maxima in the F...

Angular width of central maxima in the Fraunhofer diffraction pattern of a slit is measured. The slit is illuminated by light of wavelength `6000Å`. When the slit is illuminated by light of another wavelength, the angular width decreases by 30%. The wavelength of this light will be

A

6000 Å

B

4200 Å

C

3000 Å

D

1800 Å

Text Solution

Verified by Experts

The correct Answer is:
B
Angular width `beta= (2lambda)/(a)implies beta prop lambda`
`(beta_(1))/(beta_(2))= (lambda_(1))/(lambda_(2))= (beta)/((70)/(100)beta)= (6000)/(lambda_(2))implies lambda_(2)= 4200 Å`
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