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A radio receiver antenna that is 2 m lon...

A radio receiver antenna that is `2 m` long is oriented along the direction of the electromagnetic wave and receives a signal of intensity `5xx10^(-16) W//m^(2)`. The maximum instaneous potential difference across the two ends of the antenna is

A

`1.23 muV`

B

`1.23m V`

C

`1.23 V`

D

`12.3 mV`

Text Solution

Verified by Experts

The correct Answer is:
A
Intensity = `(1)/(2)epsilon_(0)cE_(0)^(2)`
`E_(0)= sqrt((2I)/(epsilon_(0)c))= sqrt((2 xx 5 xx 10^(-16))/(8.85 xx 10^(-12) xx 3 xx 10^(8))) implies E_(0)= 0.6 1 xx 10^(-6)(V)/(m)`
`implies E_(0)= 0.61 xx 10^(-6) (V)/(m)`
`V= E_(0)d= 0.61 xx 10^(-6) xx 2= 1.23 muV`
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