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In YDSE performed with wavelength lambda...

In YDSE performed with wavelength `lambda = 5890 Å` the angular fringe width is `0.40^(@)`. What is the angular fringe width if the entire set-up is immersed in water?

Text Solution

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The correct Answer is:
`0.30`
Angular fringe width is given by
`(beta_(theta))_("air") = = (lambda_("air"))/(d) , (beta_(theta))_("water") = (lambda_("water"))/(d)`
`((beta_(theta))_("air"))/((beta_(theta))_("water")) = (lambda_("air"))/(lambda_("water")) = (n_("air"))/(n_("water")) = (3)/(4)`
`:. (beta_(theta))_("water") = (3)/( 4) (beta_(theta))_("air") = 0. 40^(@) xx (3)/( 4) = 0.30^(@)`
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