There is a parralel plate capacitor of capacitances `2.0muF`. The voltage between the plates of parallel plate capacitor is changing at the rate of `6.0Vs^-1`. What is the displacement current in the capacitor?

Answer

12

Explanation

Here, ` C = 2 . 0 mu F = 2 xx 10^(-6) F `
`(dV)/( dt) = 6 V s^(-1)`
Displacement current
`I_(D) = epsilon_(0) A (dE)/(dt) = epsilon_(0) A (d)/(dt) ((V)/(d))`
`= (epsilon_(0) A)/( d) (dV)/(dt) = C (dV)/(dt)`
`= (2 xx 10^(-6)) xx 6 = 12 xx 10 ^(-6) A = 12 mu A `