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Two beams of ligth having intensities I ...

Two beams of ligth having intensities I and 4I interface to produce a fringe pattern on a screen. The phase difference between the beams is `(pi)/(2)` at point A and `pi` at point B. Then the difference between the resultant intensities at A and B is

A

2 I

B

4 I

C

5 I

D

7 I

Text Solution

Verified by Experts

The correct Answer is:
B
At point A-
`I_(A) = I_(1) + I_(2) + 2 sqrt(I_(1) I_(2)) cos phi `
`I_(A) = I_(1) + I_(2) = 5I`
at point B - `I_(B) = I_(1) + I_(2) - 2 sqrt(I_(1) I_(2))`
`I + 4I - 4I = I`
`I_(A) - I_(B) = 5 I - I = 4I`
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