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In Young’s double slit experiment, the w...

In Young’s double slit experiment, the wavelength of the light used is doubled and distance between two slits is half of initial distance, the resultant fringe width becomes

A

2 times

B

3 times

C

4 times

D

1/2 times

Text Solution

Verified by Experts

The correct Answer is:
C
`beta = (lambda D)/( d)`
`(beta_(1))/(beta_(2)) = (lambda)/(d) xx (d//2)/(2 lambda) rArr beta _(2) = 4 beta_(1)`
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