Home
Class 12
PHYSICS
The angular width of the central maximum...

The angular width of the central maximum in a single slit diffraction pattern is `60^(@)`. The width of the slit is `1 mu m`. The slit is illuminated by monochromatic plane waves. If another slit of same width is made near it, Young’s fringes can be observed on a screen placed at a distance 50 cm from the slits. If the observed fringe width is 1 cm, what is slit separation distance?
(i.e. distance between the centres of each slit.)

A

`75 mu m `

B

` 100 mu m `

C

`25 mu m`

D

`50 mu m`

Text Solution

Verified by Experts

The correct Answer is:
C
Angular width of central maximum ` = (2 lambda)/( a)`
`:. sin 60^(@) = (2 lambda)/( a)`
`rArr ( sqrt(3))/( 2) = (2 lambda)/( a) rArr lambda = ( sqrt(3) a)/(4)`
Fringe width in young.s double slit
` beta = (lambda D)/( d) = (D)/( d) xx ( sqrt(3) a)/( 4) rArr d = ( sqrt(3 ) a D)/( 4 beta)`
`~~ 25 mu m `
Promotional Banner

Similar Questions

Explore conceptually related problems

Angular width of central maxima of a single slit diffraction pattern is independent of

In a single slit diffraction pattern intensity and width of fringes are

Angular width of central maximum in diffraction at a single slit is……………. .

In a single-slit diffraction experiment, the width of the slit is made half of the original width:

Find the half angular width of the central bright maximum in the fraunhofer diffraction pattern of a slit of width 12xx10^(-5)cm when the slit is illuminated by monochromatic light of wavelength 6000 Å.

Find the half angular width of the central bright maximum in the fraunhofer diffraction pattern of a slit of width 12xx10^(-5)cm when the slit is illuminated by monochromatic light of wavelength 6000 Å.

The fringe width in single slit diffraction pattern is proportional to

How will the patterns in the single slit diffraction change if the width of the slit is decreased?

In a single slit diffraction pattern the angular width of a central maxima is 30^(@) . When the slit is illuminated by light of wavelength 6000Å . Then width of the slit will be approximately given as :